document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313602>Question 313602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the problem.\r<BR>\n" );
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document.write( "The number of bacteria growing in an incubation culture increases with time according to B (t) = 3300 (2)^x, where x is time in days. find the number of bacteria when x=0 and x=3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224220 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number of bacteria growing in an incubation culture increases with time according to B (t) = 3300 (2)^x, where x is time in days. find the number of bacteria when x=0 and x=3.<BR>\n" );
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document.write( "B(t) = 3300*2^x<BR>\n" );
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document.write( "B(0) = 3300*2^0<BR>\n" );
document.write( "B(0) = 3300<BR>\n" );
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document.write( "B(3) = 3300*2^3<BR>\n" );
document.write( "B(3) = 3300*8 = 26400<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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