document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4741>Question 4741</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 12 foot ladder is leaning against a wall. If the ladder reaches 8 feet high on the wall, what is the angle the ladder forms with the ground to the nearest degree? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2242 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2242\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> draw the ground, a wall and a line denoting the ladder. This situation is a right angled triangle, so you can use the basic trig relationships.\r<BR>\n" );
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document.write( "For the angle you are asked for, we know the height of the wall (opposite side) and the length of the ladder (hypotenuse)\r<BR>\n" );
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document.write( "so, sinA=opp/hyp\r<BR>\n" );
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document.write( "sinA = 8/12 --> 2/3\r<BR>\n" );
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document.write( "so angle A = sin^(-1)(2/3)\r<BR>\n" );
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document.write( "which is something...use your calculator.\r<BR>\n" );
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document.write( "Jon. </SPAN>\n" );
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