document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313514>Question 313514</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You build a box that is 4 feet long, 5 feet wide, and 8 feet high. The distance from the top left front corner to the top right back corner is ____  feet. <BR>\n" );
document.write( "The distance from the bottom left front corner to the top right back corner is _____ feet. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224179 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224179\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the base is 4 feet by 5 feet.<BR>\n" );
document.write( "the diagonal of the base has to be worked out.<BR>\n" );
document.write( "using pythagoras theorem <BR>\n" );
document.write( "4^2+5^2= diagonal ^<BR>\n" );
document.write( "25+16=diagonal^2<BR>\n" );
document.write( "sqrt39 = diagonal<BR>\n" );
document.write( "..<BR>\n" );
document.write( "the base diagonal, The distance from the bottom left front corner to the top right back corner, and the height form a right triangle.\r<BR>\n" );
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document.write( "sqrt((sqrt39)^2+8^2))= the required length<BR>\n" );
document.write( "sqrt(39+64)<BR>\n" );
document.write( "= sqrt (103) <BR>\n" );
document.write( "=10.15 feet both will be same </SPAN>\n" );
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