document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313497>Question 313497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Express as an equivalent expression that is a single<BR>\n" );
document.write( "logarithm.\r<BR>\n" );
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document.write( "logtH + logtM </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224175 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is one of the Laws of Logarithms.  When you add logarithms, you get the product of the logs.  The answer is <BR>\n" );
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document.write( "You really need to see my own website for all the FREE resources that I have there, including my OWN explanation of logarithms.  To see my website, click on my tutor name \"Rapaljer\" anywhere in algebra.com.  On my information page, click on the link to my website.  Look for the link on my Homepage \"Basic, Intermediate, and College Algebra: One Step at a Time.\"  Choose \"College Algebra\", then \"Chapter 4 (Logarithms)\".  This is my OWN non-traditional explanation, complete with examples, exercises, and ALL of the answers, that my own students found much easier to understand than the regular textbooks.\r<BR>\n" );
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document.write( "See also the vidoes that are available on this topic.  From my Homepage, look for the link \"Rapalje Vidoes in Living Color\".  These are all FREE.\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje, Retired<BR>\n" );
document.write( "Seminole State College of Florida<BR>\n" );
document.write( "Altamonte Springs Campus\r<BR>\n" );
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