document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313458>Question 313458</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following application problem (show equation and then solution) Round answers to the nearest thousandths and properly label answer. \r<BR>\n" );
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document.write( "The length of a rectangle is 5cm more than it's width.  If the area of the rectangle is 90cm^2 find the dimensions.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224174 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the width be x cm<BR>\n" );
document.write( "the length will be x+5 cm<BR>\n" );
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document.write( "Area of rectangle = L*W<BR>\n" );
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document.write( "x(x+5)=90<BR>\n" );
document.write( "x^2+5x=90<BR>\n" );
document.write( "x^2+5x-90=0<BR>\n" );
document.write( "x^2+15x-6x-90=0<BR>\n" );
document.write( "x(x+15)-6(x+15)=0<BR>\n" );
document.write( "(x+15)(x-6)=0<BR>\n" );
document.write( "x+-15 or 6.<BR>\n" );
document.write( "The width cannot be negative<BR>\n" );
document.write( "so width = 6 cm.<BR>\n" );
document.write( "Length will be 6+5=11cm </SPAN>\n" );
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