document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313459>Question 313459</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The oldest child in a family of four children is twice as old as the yougest. The two middle children are 13 and 15 years old. If the average age of the children is 14.5 , how old is the youngest child? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224143 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224143\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's have x represent the youngest and 2x will show the oldest. Now we can find the average by:<BR>\n" );
document.write( "(x+13+15+2x)/4=14.5 Rewritten as:<BR>\n" );
document.write( "(3x+28)/4=14.5 Multiply both sides by 4 to get:<BR>\n" );
document.write( "3x+28=58 Subtract 28 and divide by 3 to get:<BR>\n" );
document.write( "x=10 So the youngest is 10 years old the oldest is 20. <BR>\n" );
document.write( "Make sense?<BR>\n" );
document.write( "RJ<BR>\n" );
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