document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313471>Question 313471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i really dont understand this lesson well. so my teacher gave me this problem to do on my own and i was wondering was this right:2x-3y=12,x-y=-5\r<BR>\n" );
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document.write( "                 -3y=-2x-12               -y=-x+5<BR>\n" );
document.write( "                   y=2/3x+4                y=x+5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224129 by </B><A HREF=/tutors/aboutme.mpl?userid=OmniMaestra><B>OmniMaestra(21)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=OmniMaestra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=OmniMaestra><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224129\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So far you are doing great but you aren't finished yet. Now that you've solved both equations for y you can use the transitive property that says<BR>\n" );
document.write( "if a=y and y=b then a=b so...<BR>\n" );
document.write( "if <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2F3%29x%2B4=y ALIGN=MIDDLE  ALT=\"%282%2F3%29x%2B4=y\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=x%2B5 ALIGN=MIDDLE  ALT=\"y=x%2B5\"   DISABLED_style= \"max-width:90%; height:auto;\" > then\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2F3%29x%2B4=x%2B5 ALIGN=MIDDLE  ALT=\"%282%2F3%29x%2B4=x%2B5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Solve for x\r<BR>\n" );
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document.write( "subtract 4 from both sides:-------><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2F3%29x=x%2B5-4 ALIGN=MIDDLE  ALT=\"%282%2F3%29x=x%2B5-4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "subtract x from both sides------><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2F3%29x-x=1 ALIGN=MIDDLE  ALT=\"%282%2F3%29x-x=1\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "simplify-------------------------><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-%281%2F3%29x=1 ALIGN=MIDDLE  ALT=\"-%281%2F3%29x=1\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Multiply both sides by -3---------><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=-3 ALIGN=MIDDLE  ALT=\"x=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "now substitute the -3 into one of the original equations\r<BR>\n" );
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document.write( "-y=-x+5<BR>\n" );
document.write( "-y=-(-3)+5<BR>\n" );
document.write( "-y=8<BR>\n" );
document.write( "y=-8 </SPAN>\n" );
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