document.write( "Question 313371: (3+ √x)^2 + 3(3+√x)-10=0
\n" ); document.write( "u = (3+√x)
\n" ); document.write( "u^2= (3+√x)^2
\n" ); document.write( "u^2 + 3u - 10 = 0
\n" ); document.write( "x= [-b ± √(b^2-4ac)] ÷ 2a
\n" ); document.write( "-3 ± √(3^2-4(1)(-10)) ÷ (2)(1)
\n" ); document.write( "-3 ± √(9 + 40 )÷ 2
\n" ); document.write( "-3 ± √(49 ) ÷ 2
\n" ); document.write( "-3 + 7 = 4/2 = 2
\n" ); document.write( "-3 – 7 = -10/2 = -5\r
\n" ); document.write( "\n" ); document.write( "What did I do wrong?
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Algebra.Com's Answer #224083 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Nothing. It looks good.
\n" ); document.write( "But you're not done yet.
\n" ); document.write( "Remember you solved for u.
\n" ); document.write( "You should have u in the quadratic formula and not x.
\n" ); document.write( "Now find x using your original substitution.
\n" ); document.write( "\"u=3%2Bsqrt%28x%29\"
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