document.write( "Question 313371: (3+ √x)^2 + 3(3+√x)-10=0
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document.write( "u = (3+√x)
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document.write( "u^2= (3+√x)^2
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document.write( "u^2 + 3u - 10 = 0
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document.write( "x= [-b ± √(b^2-4ac)] ÷ 2a
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document.write( "-3 ± √(3^2-4(1)(-10)) ÷ (2)(1)
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document.write( "-3 ± √(9 + 40 )÷ 2
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document.write( "-3 ± √(49 ) ÷ 2
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document.write( "-3 + 7 = 4/2 = 2
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document.write( "-3 – 7 = -10/2 = -5\r
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document.write( "What did I do wrong? \n" );
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Algebra.Com's Answer #224083 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Nothing. It looks good. \n" ); document.write( "But you're not done yet. \n" ); document.write( "Remember you solved for u. \n" ); document.write( "You should have u in the quadratic formula and not x. \n" ); document.write( "Now find x using your original substitution. \n" ); document.write( " |