document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313348>Question 313348</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man swimming in a river finds that it takes him thrice the time to swim 2km upstream as it takes him to swim back.if the river flows at the rate of 1.5 km/hr find the swimming speed of the  man in still water </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #224059 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=224059\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a man swimming in a river finds that it takes him thrice the time to swim 2km upstream as it takes him to swim back.if the river flows at the rate of 1.5 km/hr find the swimming speed of the  man in still water<BR>\n" );
document.write( "..<BR>\n" );
document.write( "let the speed in still water be x km/hr.<BR>\n" );
document.write( "upstream the speed will be x-1.5<BR>\n" );
document.write( "distance = 2km<BR>\n" );
document.write( "time taken upstream = 2/(x-1.5)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "downstream speed = x+1.5<BR>\n" );
document.write( "distance = 2km<BR>\n" );
document.write( "time taken = 2/(x+1.5)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "he takes thrice the time upstream.\r<BR>\n" );
document.write( "\n" );
document.write( "2/(x-1.5) = 3*(2/x+1.5)<BR>\n" );
document.write( "(x+1.5)(x-1.5)=3<BR>\n" );
document.write( "x^2-2.25=3<BR>\n" );
document.write( "x^2= 0.75<BR>\n" );
document.write( "=0.87 km/hr </SPAN>\n" );
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