document.write( "Question 313332: Inside a semi circular tunnel of diameter of 22 feet, a vertical support beam is placed 5 feet from the side of the tunnel. How tall is the beam? \n" ); document.write( "

Algebra.Com's Answer #224054 by mananth(16946) $\"\"$ $\"About$

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\n" ); document.write( "The support beam is 5 feet from the end. from the ground.
\n" ); document.write( "The ground of the tunnel is the diameter of the tunnel.
\n" ); document.write( "the radius of the tunnel = 11 feet\r
\n" ); document.write( "\n" ); document.write( "so it is 5 feet from the center.
\n" ); document.write( "Let the center be O.
\n" ); document.write( "The point where the beam touches the ground be B
\n" ); document.write( "The beam touches the circumference of the tunnel at P
\n" ); document.write( "Angle OBP is a right angle
\n" ); document.write( "..
\n" ); document.write( "OBP is a right triangle
\n" ); document.write( "Leg OB = 6feet
\n" ); document.write( "Hypotenuse OP = radius of circle = 11feet\r
\n" ); document.write( "\n" ); document.write( "op^2-OB^2= leg^2
\n" ); document.write( "11^2-6^2= Leg ^2
\n" ); document.write( "121-36=leg^2
\n" ); document.write( "85= leg^2
\n" ); document.write( "sqrt85 = leg of the triangle
\n" ); document.write( "=9.22 feet. This is the height of the beam. \n" ); document.write( "

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