document.write( "Question 313258: The question is \r
\n" ); document.write( "\n" ); document.write( "Solve 2sin^2theta = 1 over 0 < theta < 2pi\r
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Algebra.Com's Answer #224035 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"2%28sin%28theta%29%29%5E2=1\"
\n" ); document.write( "\"sin%28theta%29%5E2=1%2F2\"
\n" ); document.write( "\"sin%28theta%29=0+%2B-+1%2Fsqrt%282%29=0+%2B-+sqrt%282%29%2F2\"
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\n" ); document.write( "\"theta=45\" and \"theta=135\" and \"theta=225\" and \"theta=315%7D%7D%0D%0A.%0D%0A.%0D%0A.%0D%0A%7B%7B%7B2%2Api\" radians=\"360\" degrees
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\n" ); document.write( "\"theta=45%28%282%2Api%29%2F360%29=pi%2F4\" and \"theta=135%28%282%2Api%29%2F360%29=%283%2Api%29%2F4\"
\n" ); document.write( "\"theta=225%28%282%2Api%29%2F360%29=%285%2Api%29%2F4\" and \"theta=315%28%282%2Api%29%2F360%29=%287%2Api%29%2F4\"
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