document.write( "Question 313293: I was wondering if anyone can tell me if got these right:
\n" ); document.write( "Suppose that a student needs to buy 6 books for her history course. The number of books that she will be able to find used is a binomial random variable X with n = 6 and p = 0.30. In other words, the probability that she will find any given book used is 0.30, and is independent from one book to the next. What is the expected number of used books she will find, E(X)= 1.8\r
\n" ); document.write( "\n" ); document.write( "Using Standard Normal Table, what is the probability that Z is less than or equal to 2, P(Z ≤ 2)=0.9772\r
\n" ); document.write( "\n" ); document.write( "and finally,
\n" ); document.write( "Using Standard Normal Table, find P(-0.1 < Z < 0.5)=.6687\r
\n" ); document.write( "\n" ); document.write( "Thanks for all your help,
\n" ); document.write( "Donnie
\n" ); document.write( "

Algebra.Com's Answer #224034 by stanbon(75887)\"\" \"About 
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Suppose that a student needs to buy 6 books for her history course. The number of books that she will be able to find used is a binomial random variable X with n = 6 and p = 0.30. In other words, the probability that she will find any given book used is 0.30, and is independent from one book to the next. What is the expected number of used books she will find, E(X)= np = 1.8
\n" ); document.write( "OK
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\n" ); document.write( "Using Standard Normal Table, what is the probability that Z is less than or equal to 2, P(Z ≤ 2)=0.9772
\n" ); document.write( "OK
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\n" ); document.write( "and finally,
\n" ); document.write( "Using Standard Normal Table, find P(-0.1 < Z < 0.5)=.6687
\n" ); document.write( "No. I get 0.2313
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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