document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35991>Question 35991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help\r<BR>\n" );
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document.write( "4)Amanda has 400 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). She wants to maximize the area of her patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation.\r<BR>\n" );
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document.write( "Answer:  <BR>\n" );
document.write( "Show work in this space.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22403 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE THE FOLLOWING AND TRY<BR>\n" );
document.write( "LET LENGTH BE L AND WIDTH BE W<BR>\n" );
document.write( "WE HAVE PERIMETER =2(L+W)=300<BR>\n" );
document.write( "L+W=150<BR>\n" );
document.write( "W=150-L.............................I<BR>\n" );
document.write( "AREA =LW=L(150-L)= - (L^2-150L) = - {(L^2-2*L*75+75^2)-75^2}<BR>\n" );
document.write( "= 75^2 - (L-75)^2.......SINCE (L-75)^2 IS ALWAYS POSITIVE ,AND IT IS<BR>\n" );
document.write( "TO BE SUBTRACTED FROM 75^2 TO GET THE AREA,WE GET MAXIMUM AREA WHEN<BR>\n" );
document.write( "THIS IS MINIMUM...OR...L-75=0....OR....L=75<BR>\n" );
document.write( "SO FOR MAXIMUM AREA THE PATIO SHOULD BE A SQUARE OF 75' LENGTH AND 75' WIDTH. </SPAN>\n" );
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