document.write( "Question 313284: 62(200
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document.write( "Solution A is 80% Alcohol and Solution B is 30% Alcohol. How many Liters of each Solutions should be mixed in order to make 200 liters of a Solution that is 62% Alcohol ? \n" );
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Algebra.Com's Answer #224027 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! 1. \n" ); document.write( "2. \n" ); document.write( "Multiply eq.2 by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Then from eq. 2, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "128 liters of 80% solution and 72% of the 30% solution. \n" ); document.write( " |