document.write( "Question 313259: Hello I have a problem, but cant seem to find out what i am doing wrong. The equations are solutions to systems of linear equations in three variables.\r
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document.write( "2x+ y-3z=-12
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document.write( "3x-2y-z= 3
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document.write( "-x+5y+2z=-3\r
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document.write( "I know you have to work only two equations at a time. My teacher took the class through it step by step but i'm thinking im making a mistake on my adding or subtracting because i keep coming out with the wrong answer.
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document.write( "THanks
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document.write( "Kayla \n" );
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Algebra.Com's Answer #224010 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 2x+ y-3z=-12 \n" ); document.write( "3x-2y-z= 3 \n" ); document.write( "-x+5y+2z=-3 \n" ); document.write( ".. \n" ); document.write( "2x+ y-3z=-12 ( multiply by 2 to eliminate y) \n" ); document.write( "3x-2y-z= 3. \n" ); document.write( ".. \n" ); document.write( "4x+2y-6z+3x-2y-z= -24+3 \n" ); document.write( "7x-7z=-21. \n" ); document.write( "x-z=-3 \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "3x-2y-z= 3 ( multiply by 5 to eliminate y) \n" ); document.write( "-x+5y+2z=-3 ( multiply by 2) and add \n" ); document.write( "15x-10y-5z-2x+10y+4z=15-6 \n" ); document.write( "13x-z=9. \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "x-z=-3 \n" ); document.write( "13x-z=9 \n" ); document.write( ".. \n" ); document.write( "13x-13z-13x+z=-39-9 \n" ); document.write( "-12z=-48 \n" ); document.write( "z= 4. \n" ); document.write( ".. \n" ); document.write( "plug the value of z in x-z = -3 \n" ); document.write( "x-4=-3 \n" ); document.write( "x=4-3 \n" ); document.write( "x=1. \n" ); document.write( ".. \n" ); document.write( "plug the values of x & z in the equation 2x+ y-3z=-12 \n" ); document.write( "2+y-12=-12 \n" ); document.write( "y=-2 \n" ); document.write( " |