document.write( "Question 35971: Amber has five dollars in her purse consistent of nickels, dimes and quarters. If she has one more quarter then dimes, and one less nickel then dimes, how many of each type of coin does she have \n" ); document.write( "
Algebra.Com's Answer #22401 by venugopalramana(3286)\"\" \"About 
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Amber has five dollars in her purse consistent of nickels(N SAY) , dimes ( D SAY )and quarters (Q SAY ) . If she has one more quarter then dimes,
\n" ); document.write( "D+1=Q.............I
\n" ); document.write( " and one less nickel then dimes,
\n" ); document.write( "D-1=N...................II
\n" ); document.write( " how many of each type of coin does she have
\n" ); document.write( "TOTAL IS 5 $=500 CENTS
\n" ); document.write( "25Q+10D+5N=500......................
\n" ); document.write( "5Q+2D+N=100...........................III.......SUBSTITUTING FROM EQN.I AND EQN.II
\n" ); document.write( "5(D+1)+2D+D-1=100
\n" ); document.write( "5D+5+2D+D-1=100
\n" ); document.write( "8D=100-5+1=96
\n" ); document.write( "D=96/8=12
\n" ); document.write( "HENC
\n" ); document.write( "D=12................12*10=120 CENTS
\n" ); document.write( "N=12-1=11............11*5= 55 CENTS
\n" ); document.write( "Q=12+1=13...........13*25=325 CENTS
\n" ); document.write( "TOTAL.....................500 CENTS = 5 $ \n" ); document.write( "
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