document.write( "Question 313259: Hello I have a problem, but cant seem to find out what i am doing wrong. The equations are solutions to systems of linear equations in three variables.\r
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document.write( "2x+ y-3z=-12
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document.write( "3x-2y-z= 3
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document.write( "-x+5y+2z=-3\r
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document.write( "I know you have to work only two equations at a time. My teacher took the class through it step by step but i'm thinking im making a mistake on my adding or subtracting because i keep coming out with the wrong answer.
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document.write( "THanks
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document.write( "Kayla \n" );
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Algebra.Com's Answer #224007 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 2x+ y-3z=-12 \n" ); document.write( "3x-2y-z= 3 \n" ); document.write( "-x+5y+2z=-3 \n" ); document.write( "------------- \n" ); document.write( "To use elimination, pick one of the variables to eliminate. \n" ); document.write( "I'll eliminate z \n" ); document.write( "Multiply eqn 2 by 2 and add it to eqn 3. \n" ); document.write( "Then multiply eqn 2 by 3 and subtract it from eqn 1 \n" ); document.write( "------------- \n" ); document.write( "3x-2y-z= 3 x2 --> 6x-4y-2z = 6 \n" ); document.write( "-x+5y+2z=-3 \n" ); document.write( "6x-4y-2z = 6 \n" ); document.write( "------------ Add \n" ); document.write( "5x + y = 3 Eqn A \n" ); document.write( "---------- \n" ); document.write( "2x+ y-3z=-12 \n" ); document.write( "3x-2y-z= 3 x3 --> 9x-6y-3z = 9 \n" ); document.write( "2x+ y-3z=-12 \n" ); document.write( "9x-6y-3z = 9 \n" ); document.write( "------------ Subtract \n" ); document.write( "-7x+5y = -21 Eqn B \n" ); document.write( "-------------------- \n" ); document.write( "Now eqns A and B are in x and y only \n" ); document.write( "-7x+5y = -21 Eqn B \n" ); document.write( "25x+5y = 15 Eqn A times 5 \n" ); document.write( "------------ Subtract \n" ); document.write( "-32x = -36 \n" ); document.write( "x = 9/8 \n" ); document.write( "-------- \n" ); document.write( "Sub for x into Eqn A or B \n" ); document.write( "5*(9/8) + y = 3 \n" ); document.write( "y = 3 - 45/8 \n" ); document.write( "y = -21/8 \n" ); document.write( "---------- \n" ); document.write( "Sub for x and y into eqn 2 (or any of the original 3) \n" ); document.write( "3x-2y-z= 3 \n" ); document.write( "3*(9/8) - 2*(-21/8) - z = 3 \n" ); document.write( "z = -3 + 27/8 + 42/8 = -3 + 69/8 \n" ); document.write( "z = 45/8 \n" ); document.write( " \n" ); document.write( " |