document.write( "Question 313263: . Find the value of k such that the graphs of x + 7y = 70 and y + 3 = kx are perpendicular. \n" ); document.write( "
Algebra.Com's Answer #223998 by OmniMaestra(21)\"\" \"About 
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First find the slope of the known equation:\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+7y+=+70\"\r
\n" ); document.write( "\n" ); document.write( "change the equation to slope-intercept form.\r
\n" ); document.write( "\n" ); document.write( "solve for y, subtract x from both sides \"7y+=+-x+%2B+70\"\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 7------------------\"7y%2F7=%28-x%2F7%29+%2B+%2870%2F7%29\"\r
\n" ); document.write( "\n" ); document.write( "Simplify into slope-intercept form------\"y+=+%28-1%2F7%29x+%2B+10\"\r
\n" ); document.write( "\n" ); document.write( "So the slope is -1/7. The slope of the perpendiculoar line must be the inverse reciprocal of the original. \"-1%2F7\" becomes \"7%2F1+=+7\" \r
\n" ); document.write( "\n" ); document.write( "Now solve the second equation for y. ---- \"y+=+kx+-3\"\r
\n" ); document.write( "\n" ); document.write( "replace k with the new slope--------------\"y=7x-3\", so k = 7
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