document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313237>Question 313237</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs a saline solution that is 20% sodium chloride but only has solutions that are 15% and 40% sodium chloride. If the chemist measures 150 mL of the 15% solution, how many mililiters of the 40% solution should she add to make 20% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223990 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223990\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .40X+.15*150=.20(150+X)<BR>\n" );
document.write( ".40X+22.5=30+.20X<BR>\n" );
document.write( ".40X-.20X=30-22.5<BR>\n" );
document.write( ".20X=7.5<BR>\n" );
document.write( "X=7.5/.20<BR>\n" );
document.write( "X=37.5 ml OF THE 40% SOLUTION IS NEEDED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".40*37.5+.15*150=.20(150+37.5)<BR>\n" );
document.write( "15+22.5=.20*187.5<BR>\n" );
document.write( "37.5=37.5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );