document.write( "Question 313057: An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and t is the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 150 meters tall. If the initial speed is 35 meters per second, how high above the ground will the pebble be after 3 seconds? \n" ); document.write( "

Algebra.Com's Answer #223988 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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An object's altitude, in meters, is given by the polynomial h + vt - 9.8t^2, where
\n" ); document.write( " h is the height in meters from which the launch occurs, v is the initial upward
\n" ); document.write( "speed in meters per second, and t is the number of seconds for which the rocket
\n" ); document.write( "is airborne.
\n" ); document.write( " A pebble is shot upward from the top of a building 200 meters tall.
\n" ); document.write( " If the initial speed is 30 meters per second, how high above the ground will the pebble be after 4 seconds?
\n" ); document.write( ":
\n" ); document.write( "f(t) = height of pebble in t seconds
\n" ); document.write( "The equation
\n" ); document.write( "f(t) = -9.8t^2 + 30t + 200
\n" ); document.write( "t = 4 sec
\n" ); document.write( "f(4) = -9.8(4^2) + 30(4) + 200
\n" ); document.write( "f(4) = -9.8(16) + 120 + 200
\n" ); document.write( "f(4) = 156.8 + 120 + 200
\n" ); document.write( "f(4) = 163.2 m after 4 sec \n" ); document.write( "

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