document.write( "Question 36480This question is from textbook
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document.write( ": Jon is 6 years older than his wife Liz. In 4 years, twice his age plus 1 will be 3 times Liz's age 3 years ago. How old are they now? \n" );
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Algebra.Com's Answer #22398 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let x = Liz's present age \n" ); document.write( "x+ 6 = Jon's present age\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In 4 years Liz will be x + 4, and John will be x+ 10. \n" ); document.write( "Three years ago, Liz was x - 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The second sentence is the equation:\r \n" ); document.write( "\n" ); document.write( "In 4 years, twice Jon's age plus 1 will be 3 times Liz's age 3 years ago.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 2x from each side and add +9 to each side:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Liz is 30.\r \n" ); document.write( "\n" ); document.write( "Jon is 34. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In 6 years Jon will be 40, and twice his age +1 will be 2*40+1 = 81.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Three years ago, Liz was 27, so three times her age three years ago is also 81. \r \n" ); document.write( "\n" ); document.write( "It checks!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |