document.write( "Question 36480This question is from textbook
\n" ); document.write( ": Jon is 6 years older than his wife Liz. In 4 years, twice his age plus 1 will be 3 times Liz's age 3 years ago. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #22398 by rapaljer(4671)\"\" \"About 
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Let x = Liz's present age
\n" ); document.write( "x+ 6 = Jon's present age\r
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\n" ); document.write( "\n" ); document.write( "In 4 years Liz will be x + 4, and John will be x+ 10.
\n" ); document.write( "Three years ago, Liz was x - 3\r
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\n" ); document.write( "\n" ); document.write( "The second sentence is the equation:\r
\n" ); document.write( "\n" ); document.write( "In 4 years, twice Jon's age plus 1 will be 3 times Liz's age 3 years ago.\r
\n" ); document.write( "\n" ); document.write( "\"+2+%28x%2B10%29+%2B1+=+3%28x-3%29+\"
\n" ); document.write( "\"2x+%2B+20+%2B+1+=+3x+-+9+\"\r
\n" ); document.write( "\n" ); document.write( "\"2x+%2B+21+=+3x+-+9\"\r
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\n" ); document.write( "\n" ); document.write( "Subtract 2x from each side and add +9 to each side:\r
\n" ); document.write( "\n" ); document.write( "\"2x-2x+%2B+21+=+3x+-2x+-+9\"
\n" ); document.write( "\"21+=+x+-+9\"\r
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\n" ); document.write( "\n" ); document.write( "\"21+%2B+9+=+x+-9%2B9+\"
\n" ); document.write( "\"+30+=+x\"\r
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\n" ); document.write( "\n" ); document.write( "Liz is 30.\r
\n" ); document.write( "\n" ); document.write( "Jon is 34. \r
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\n" ); document.write( "\n" ); document.write( "In 6 years Jon will be 40, and twice his age +1 will be 2*40+1 = 81.\r
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\n" ); document.write( "\n" ); document.write( "Three years ago, Liz was 27, so three times her age three years ago is also 81. \r
\n" ); document.write( "\n" ); document.write( "It checks!!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC\r
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