document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313138>Question 313138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor  4x(x - 3)minus 5(3 - x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223887 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, use this trick to make the 3-x term the same as the x-3 term:\r<BR>\n" );
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document.write( "-(3-x)=-3+x = x-3\r<BR>\n" );
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document.write( "So you can turn 3-x into x-3 if you put a negative sign in front of it:\r<BR>\n" );
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document.write( "4x(x-3) - 5(3-x)<BR>\n" );
document.write( "4x(x-3) + 5(x-3)   [note I applied the trick here, which turned -5 into +5]<BR>\n" );
document.write( "(4x+5)(x-3) </SPAN>\n" );
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