document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=313088>Question 313088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 90cm, its width is half its length. What would the equation be to solve this? I think it is 2L+2(1/2L)=90 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223872 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is half the length and the perimeter is 90 cm.\r<BR>\n" );
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document.write( "Twice the length plus twice the width = 90 cm.\r<BR>\n" );
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document.write( "2L + 2(L/2) = 3L = 90 cm.\r<BR>\n" );
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document.write( "L = 30 cm.\r<BR>\n" );
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document.write( "Therefore we have a rectangle with a length 30 cm and width 15 cm.<BR>\n" );
document.write( "This satisfies the criteria.\r<BR>\n" );
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document.write( "NB 2L+2(1/2L)=90.<BR>\n" );
document.write( "Written 1/2L could mean L/2 or 1/(2L) since the L looks in line with the 2. We know it is supposed to be above the 2 and you meant L/2. It is clearer to write L/2 than 1/2L. </SPAN>\n" );
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