document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35927>Question 35927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help with this question?\r<BR>\n" );
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document.write( "Say that the variance of a set of data is 24/5.  At a minimum, about how many data points will be within 4.3818 of the mean of measurements?\r<BR>\n" );
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document.write( "A. 4/5<BR>\n" );
document.write( "B. 3/4<BR>\n" );
document.write( "C. 2/3<BR>\n" );
document.write( "D.1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22368 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22368\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> VARIANCE =24/5<BR>\n" );
document.write( "RMS DEVIATION =SIGMA=S SAY = SQRT(24/5)=2.191<BR>\n" );
document.write( "HENCE THE DEVATION OF 4.3818 IS AMOUNTING TO 2*S VARIATION...AS PER NORMAL DISTRIBUTION OVER 95% OF DATA ARE ON THIS 2S DEVIATION LEVEL.HENCE A IS MOST APPROPRIATE ANSWER THOUGH IT IS ONLY 80% </SPAN>\n" );
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