document.write( "Question 312755: A bag contains 5 yellow marbles, 16 green marbles, and 2 red marbles. What is the chance of drawing a red marble? If a red marble is drawn the first time and then a second marble is drawn without replacement, what is the probability of drawing a yellow marble? Give solutions exactly in reduced fraction from separated by a comma?\r
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document.write( "I do not have a clue? \n" );
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Algebra.Com's Answer #223608 by Fombitz(32388) You can put this solution on YOUR website! 5 yellow, Y \n" ); document.write( "16 green, G \n" ); document.write( "2 red, R \n" ); document.write( "Add them up to get 23 total marbles. \n" ); document.write( "P(event)=number of outcomes of that event/total outcomes. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "1. So the chance of drawing a red marble is, \n" ); document.write( "P(R)=Red Marbles/Total Marbles= \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Once you chose a red marble and don't replace it, the marble count changes, you then have 1 red marble and 22 total marbles. The probability of picking a red then changes to \n" ); document.write( "P(R)= \n" ); document.write( "The total probability of picking two reds in a row is the product of both probabilities. \n" ); document.write( "P(2 R)= \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "P(Y)=Yellow marbles/Total marbles= \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Just for fun, \n" ); document.write( "P(G)=Green marbles/Total marbles= \n" ); document.write( "Also note, \n" ); document.write( "P(Y)+P(R)+P(G)= \n" ); document.write( "which means that picking a marble gives you 100% chance of picking either a yellow one, a red one, or a green one, since those are the only choices available. \n" ); document.write( " |