document.write( "Question 312755: A bag contains 5 yellow marbles, 16 green marbles, and 2 red marbles. What is the chance of drawing a red marble? If a red marble is drawn the first time and then a second marble is drawn without replacement, what is the probability of drawing a yellow marble? Give solutions exactly in reduced fraction from separated by a comma?\r
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Algebra.Com's Answer #223608 by Fombitz(32388)\"\" \"About 
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5 yellow, Y
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\n" ); document.write( "Add them up to get 23 total marbles.
\n" ); document.write( "P(event)=number of outcomes of that event/total outcomes.
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\n" ); document.write( "1. So the chance of drawing a red marble is,
\n" ); document.write( "P(R)=Red Marbles/Total Marbles=\"2%2F23\"
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\n" ); document.write( "Once you chose a red marble and don't replace it, the marble count changes, you then have 1 red marble and 22 total marbles. The probability of picking a red then changes to
\n" ); document.write( "P(R)=\"1%2F22\".
\n" ); document.write( "The total probability of picking two reds in a row is the product of both probabilities.
\n" ); document.write( "P(2 R)=\"%282%2F23%29%281%2F22%29=1%2F253\"
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\n" ); document.write( "P(Y)=Yellow marbles/Total marbles=\"5%2F23\"
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\n" ); document.write( "Just for fun,
\n" ); document.write( "P(G)=Green marbles/Total marbles=\"16%2F23\".
\n" ); document.write( "Also note,
\n" ); document.write( "P(Y)+P(R)+P(G)=\"%285%2F23%29%2B%282%2F23%29%2B%2816%2F23%29=23%2F23=1\"
\n" ); document.write( "which means that picking a marble gives you 100% chance of picking either a yellow one, a red one, or a green one, since those are the only choices available.
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