document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=312721>Question 312721</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36in, find the length of the side of a regular hexagon   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223587 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> equilater triangle <BR>\n" );
document.write( "perimeter = 36<BR>\n" );
document.write( "so each side = 12in<BR>\n" );
document.write( "..<BR>\n" );
document.write( "height of equilateral triangle = (sqrt3)s /2   s= side of triangle<BR>\n" );
document.write( "h= 6*sqrt3 / 2<BR>\n" );
document.write( "h= 3sqrt3<BR>\n" );
document.write( "= 5.2 in<BR>\n" );
document.write( "..<BR>\n" );
document.write( "area of triangle = 1/ * base * height<BR>\n" );
document.write( "= 1/2 *6 *5.2<BR>\n" );
document.write( "=3*5.2<BR>\n" );
document.write( "=15.6 sq.in<BR>\n" );
document.write( "..<BR>\n" );
document.write( "so area of hexagon = 15.6<BR>\n" );
document.write( "area of hexagon = 3sqrt(3)/2 * s^2 s= side of polygon<BR>\n" );
document.write( "=36*3*sqrt(3) / 2 <BR>\n" );
document.write( "= 93.53 sq. inches </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );