document.write( "Question 312688: A TRAIN LEAVES D.C. AT NOON TRAVELING NORTH AT 44 MPH. ONE HOUR LATER, ANOTHER TRAIN GOING 52 MPH TRAVELS NORTH ON A PARALLEL TRACK. HOW MANY HOURS WILL THE SECOND TRAIN TRAVEL BEFORE IT OVERTAKES THE FIRST TRAIN? \n" ); document.write( "
Algebra.Com's Answer #223555 by mananth(16946)![]() ![]() You can put this solution on YOUR website! train A leaves 12 noon at 44 mph. \n" ); document.write( "Train B leaves at 1 pm at 52 mph \n" ); document.write( ".. \n" ); document.write( "Before train B leaves DC train A has traveled 44*1 = 44 miles. \n" ); document.write( "From this point let train A travel x miles before they meet. \n" ); document.write( ".. \n" ); document.write( "So train B travels x+44 miles to catch up with train. \n" ); document.write( ".. \n" ); document.write( "time taken by train A = x/44 \n" ); document.write( "time taken by train B = x+44 / 52 \n" ); document.write( ".. \n" ); document.write( "x/44 = x+44 / 52 \n" ); document.write( "52x =44*(x+44) \n" ); document.write( "52x=44x +1936 \n" ); document.write( "8x=1936 \n" ); document.write( "x= 242 miles. \n" ); document.write( "Train B has to travel 242+44=286 miles to catch up. \n" ); document.write( "its speed is 52 mph \n" ); document.write( "time taken = 286/52 \n" ); document.write( "=5.5 hours \n" ); document.write( " |