document.write( "Question 36349: Here I need to factor the quadratic expression completely, and find the roots of the expression.\r
\n" ); document.write( "\n" ); document.write( "135x^2 - 222x + 91
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Algebra.Com's Answer #22352 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
This is a hard one to factor but it can be done with a bit of trial & error:
\n" ); document.write( "The factors of 135 are:
\n" ); document.write( "1 X 135 = 135
\n" ); document.write( "3 X 45 = 135
\n" ); document.write( "5 X 27 = 135
\n" ); document.write( "9 X 15 = 135
\n" ); document.write( "The factors of 91 are:
\n" ); document.write( "1 X 91 = 91
\n" ); document.write( "7 X 13 = 91\r
\n" ); document.write( "\n" ); document.write( "You can try various combinations of these but the sum (or the difference) of the factors for the x-term must equal -222.
\n" ); document.write( "For example:
\n" ); document.write( "\"%2815x+-+13%29%289x+-+7%29+=+135x%5E2+-+222x+%2B+91\"
\n" ); document.write( "To find the roots, we must have an equation, so you can set the expression equal to zero.
\n" ); document.write( "\"135x%5E2+-+222x+%2B+91+=+0\" Factor.
\n" ); document.write( "\"%2815x+-+13%29%289x+-+7%29+=+0\" Apply the zero products principle.
\n" ); document.write( "\"15x+-+13+=+0\" and/or \"9x+-+7+=+0\"
\n" ); document.write( "If \"15x+-+13+=+0\" then \"15x+=+13\" and \"x+=+13%2F15\"
\n" ); document.write( "If \"9x+-+7+=+0\" then \"9x+=+7\" and \"x+=+7%2F9\"
\n" ); document.write( "The factors are: (15x - 13) and (9x - 7)
\n" ); document.write( "The roots are: \"x+=+13%2F15\" and \"x+=+7%2F9\"
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