document.write( "Question 312492: Jim has a total of 50 coins. Some are nickels and some are quarters. Altogether he has $4.10. How many quarters does he have? How many nickels? \n" ); document.write( "
Algebra.Com's Answer #223499 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Write an equation for each statement; n = no.of nickels; q = no. of quarters \n" ); document.write( ": \n" ); document.write( "\"Jim has a total of 50 coins.\" \n" ); document.write( "n + q = 50 \n" ); document.write( "n = (50-q); use this form for substitution \n" ); document.write( ": \n" ); document.write( "\"Some are nickels and some are quarters. Altogether he has $4.10.\" \n" ); document.write( ".05n + .25q = 4.10 \n" ); document.write( "Substitute (50-q) for n \n" ); document.write( ".05(50-q) + .25q = 4.10 \n" ); document.write( ": \n" ); document.write( "2.5 - .05q + .25q = 4.10 \n" ); document.write( ": \n" ); document.write( "-.05q + .25q = 4.10 - 2.50 \n" ); document.write( ": \n" ); document.write( ".20q = 1.60 \n" ); document.write( "q = \n" ); document.write( "q = 8 quarters \n" ); document.write( "then \n" ); document.write( "50 - 8 = 42 nickels \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution: \n" ); document.write( "42(.05) + 8(.25) \n" ); document.write( "2.10 + 2.00 = 4.10\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |