document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=312502>Question 312502</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular field is 50 meters more than twice it's length. If the perimeter is 700 meters, find the dimensions of the field. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223463 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W+50<BR>\n" );
document.write( "P=2L+2W<BR>\n" );
document.write( "700=2(2W+50)+2W<BR>\n" );
document.write( "700=4W+100+2W<BR>\n" );
document.write( "700=6W+100<BR>\n" );
document.write( "6W=700-100<BR>\n" );
document.write( "6W=600<BR>\n" );
document.write( "W=600/6<BR>\n" );
document.write( "W=100 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "L=2*100+50=200+50=250 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "700=2*250+2*100<BR>\n" );
document.write( "700=500+200<BR>\n" );
document.write( "700=700 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );