document.write( "Question 312531: The sum of the squares of two consecutive positive numbers is 41. What is the smaller number? \n" ); document.write( "
Algebra.Com's Answer #223460 by checkley77(12844)\"\" \"About 
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LET X & X+1 BE THE 2 NUMBERS.
\n" ); document.write( "41=X^2+(X+1)^2
\n" ); document.write( "41=X^2+X^2+2X+1
\n" ); document.write( "2X^2+2X+1-41=0
\n" ); document.write( "2X^2+2X-40=0
\n" ); document.write( "2(X^2+X+420)=0
\n" ); document.write( "2(X+5)(X-4)=0
\n" ); document.write( "X-4=0
\n" ); document.write( "X=4 ANS FOR THE SMALLER NUMBER.
\n" ); document.write( "PROOF:
\n" ); document.write( "41=4^2+(4+1)^2
\n" ); document.write( "41=16+5^2
\n" ); document.write( "41=16+25
\n" ); document.write( "41=41
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