document.write( "Question 312531: The sum of the squares of two consecutive positive numbers is 41. What is the smaller number? \n" ); document.write( "
Algebra.Com's Answer #223460 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! LET X & X+1 BE THE 2 NUMBERS. \n" ); document.write( "41=X^2+(X+1)^2 \n" ); document.write( "41=X^2+X^2+2X+1 \n" ); document.write( "2X^2+2X+1-41=0 \n" ); document.write( "2X^2+2X-40=0 \n" ); document.write( "2(X^2+X+420)=0 \n" ); document.write( "2(X+5)(X-4)=0 \n" ); document.write( "X-4=0 \n" ); document.write( "X=4 ANS FOR THE SMALLER NUMBER. \n" ); document.write( "PROOF: \n" ); document.write( "41=4^2+(4+1)^2 \n" ); document.write( "41=16+5^2 \n" ); document.write( "41=16+25 \n" ); document.write( "41=41 \n" ); document.write( " \n" ); document.write( " |