document.write( "Question 36450: The inventor of a new product believes that the cost of producing the product is given by the function C(x) = 1.75x + 7000. If the inventor charges $4 per unit, then her profit for producing and selling x units is given by the function P(x) = 2.25x – 7000\r
\n" );
document.write( "\n" );
document.write( "(a) What is her profit if she sells 2000 units?\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( " (b) What is her profit if she sells 5000 units?\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "(c) What is the break-even point for sales stated in the number of units?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #22343 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If the inventor in the above exercise charges $4 per unit, then her profit for producing and selling units is given by the function \r \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "a. What is her profit if she sells 2000 units?\r \n" ); document.write( "\n" ); document.write( "b. What is her profit if she sells 500 units\r \n" ); document.write( "\n" ); document.write( "c. What is the break-even point for sales?\r \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "a. P(2000)= 2.25(2000)-7000= loss of $2500 \r \n" ); document.write( "\n" ); document.write( "b.P(500) = 2.25(500)-7000= loss of $5875\r \n" ); document.write( "\n" ); document.write( "c.Break-even means Cost = Profit\r \n" ); document.write( "\n" ); document.write( " 1.75x+7000=2.25-7000\r \n" ); document.write( "\n" ); document.write( " 0.5x=14000\r \n" ); document.write( "\n" ); document.write( " x= 28000 units\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |