document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=312439>Question 312439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a three digit number such that if the digits at the tens place and the hundreds place are reversed then the number obtained is twenty percent greater than the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223377 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223377\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find a three digit number such that if the digits at the tens place and the hundreds place are reversed then the number obtained is twenty percent greater than the original number.\r<BR>\n" );
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document.write( "b*100 + a*10 + c = 1.2 * (a*100 + b*10 + c)<BR>\n" );
document.write( "100b + 10a + c = 120a + 12b + 1.2c<BR>\n" );
document.write( "10a - 120a + 100b - 12b + c - 1.2c = 0<BR>\n" );
document.write( "-110a + 88b - 0.2c = 0<BR>\n" );
document.write( "110a - 88b + 0.2c = 0 (divided by -1)<BR>\n" );
document.write( "set c = 0<BR>\n" );
document.write( "try 9 -> 4+5=9, 5+4=9<BR>\n" );
document.write( "110(4) - 88(5) = 440 - 440 = 0<BR>\n" );
document.write( "x = 1.2 * 450<BR>\n" );
document.write( "x = 540<BR>\n" );
document.write( "the 3 digit number is 450<BR>\n" );
document.write( " </SPAN>\n" );
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