document.write( "Question 312378: Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each? \n" ); document.write( "
Algebra.Com's Answer #223363 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each?\r
\n" ); document.write( "\n" ); document.write( ".
\n" ); document.write( "Let x = Tony's age
\n" ); document.write( "then from \"Belinda is 8 more than twice Tony’s age.\"
\n" ); document.write( "2x+8 = Belinda's age
\n" ); document.write( ".
\n" ); document.write( "From:\"Tony and Belinda have a combined age of 56\" we get our equation:
\n" ); document.write( "x + 2x+8 = 56
\n" ); document.write( "3x+8 = 56
\n" ); document.write( "3x = 48
\n" ); document.write( "x = 16 years old (Tony)
\n" ); document.write( ".
\n" ); document.write( "Belinda:
\n" ); document.write( "2x+8 = 2(16)+8 = 16+8 = 24 years old
\n" ); document.write( "
\n" );