document.write( "Question 312378: Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each? \n" ); document.write( "
Algebra.Com's Answer #223363 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each?\r \n" ); document.write( "\n" ); document.write( ". \n" ); document.write( "Let x = Tony's age \n" ); document.write( "then from \"Belinda is 8 more than twice Tony’s age.\" \n" ); document.write( "2x+8 = Belinda's age \n" ); document.write( ". \n" ); document.write( "From:\"Tony and Belinda have a combined age of 56\" we get our equation: \n" ); document.write( "x + 2x+8 = 56 \n" ); document.write( "3x+8 = 56 \n" ); document.write( "3x = 48 \n" ); document.write( "x = 16 years old (Tony) \n" ); document.write( ". \n" ); document.write( "Belinda: \n" ); document.write( "2x+8 = 2(16)+8 = 16+8 = 24 years old \n" ); document.write( " |