document.write( "Question 312382: The number of books N to be sold at a bookfare is given by the function \r
\n" ); document.write( "\n" ); document.write( "N(p) = 25000 / (3p + k)\r
\n" ); document.write( "\n" ); document.write( "where p is the price per book and k is a constant. If 1000 books are sold at $7 per book, how many books will be sold at the price of $10 per book?
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Algebra.Com's Answer #223346 by nerdybill(7384)\"\" \"About 
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The number of books N to be sold at a bookfare is given by the function
\n" ); document.write( "N(p) = 25000 / (3p + k)
\n" ); document.write( "where p is the price per book and k is a constant. If 1000 books are sold at $7 per book, how many books will be sold at the price of $10 per book?
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\n" ); document.write( "First, use: \"1000 books are sold at $7 per book\" to find k:
\n" ); document.write( "N(p) = 25000 / (3p + k)
\n" ); document.write( "1000 = 25000 / (3(7) + k)
\n" ); document.write( "1000 = 25000 / (21 + k)
\n" ); document.write( "1000(21 + k) = 25000
\n" ); document.write( "21000 + 1000k = 25000
\n" ); document.write( "1000k = 4000
\n" ); document.write( "k = 4
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\n" ); document.write( "Our formula is now:
\n" ); document.write( "N(p) = 25000 / (3p + 4)
\n" ); document.write( "Now we can answer: \"how many books will be sold at the price of $10 per book?\"
\n" ); document.write( "N(p) = 25000 / (3(10) + 4)
\n" ); document.write( "N(p) = 25000 / (30 + 4)
\n" ); document.write( "N(p) = 25000/34
\n" ); document.write( "N(p) = 735.29
\n" ); document.write( "But, since we can't sell a partial book:
\n" ); document.write( "N(p) = 735\r
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