document.write( "Question 312382: The number of books N to be sold at a bookfare is given by the function \r
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document.write( "N(p) = 25000 / (3p + k)\r
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document.write( "where p is the price per book and k is a constant. If 1000 books are sold at $7 per book, how many books will be sold at the price of $10 per book?
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Algebra.Com's Answer #223346 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The number of books N to be sold at a bookfare is given by the function \n" ); document.write( "N(p) = 25000 / (3p + k) \n" ); document.write( "where p is the price per book and k is a constant. If 1000 books are sold at $7 per book, how many books will be sold at the price of $10 per book? \n" ); document.write( ". \n" ); document.write( "First, use: \"1000 books are sold at $7 per book\" to find k: \n" ); document.write( "N(p) = 25000 / (3p + k) \n" ); document.write( "1000 = 25000 / (3(7) + k) \n" ); document.write( "1000 = 25000 / (21 + k) \n" ); document.write( "1000(21 + k) = 25000 \n" ); document.write( "21000 + 1000k = 25000 \n" ); document.write( "1000k = 4000 \n" ); document.write( "k = 4 \n" ); document.write( ". \n" ); document.write( "Our formula is now: \n" ); document.write( "N(p) = 25000 / (3p + 4) \n" ); document.write( "Now we can answer: \"how many books will be sold at the price of $10 per book?\" \n" ); document.write( "N(p) = 25000 / (3(10) + 4) \n" ); document.write( "N(p) = 25000 / (30 + 4) \n" ); document.write( "N(p) = 25000/34 \n" ); document.write( "N(p) = 735.29 \n" ); document.write( "But, since we can't sell a partial book: \n" ); document.write( "N(p) = 735\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |