document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=312442>Question 312442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Five hundred feet of fencing is available to enclose a rectangular pasture alongside a river, which serves as one side of the rectangle. Express the area of the rectangular pasture as a function of x. (only 3 sides require fencing) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223344 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Five hundred feet of fencing is available to enclose a rectangular pasture alongside a river, which serves as one side of the rectangle. Express the area of the rectangular pasture as a function of x. (only 3 sides require fencing)<BR>\n" );
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document.write( "Draw a diagram of the problem -- it'll help you see the solution.<BR>\n" );
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document.write( "Let x = width of rectangular pasture<BR>\n" );
document.write( "then<BR>\n" );
document.write( "500-2x = lenght of rectangular pasture<BR>\n" );
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document.write( "Area = x(500-2x)<BR>\n" );
document.write( "Area = 500x-2x^2<BR>\n" );
document.write( "Area = -2x^2+500x<BR>\n" );
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