document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=312407>Question 312407</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A school club is planning a bus trip to the wildlife park. A bus which will hold up to 45 people will cost 600 dollars and admission tickets cost 30 dollars each.\r<BR>\n" );
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document.write( "If you intend to charge each person 50 dollars, including bus and admission ticket, what is the minimum number of people who must participate to ensure that these costs are covered? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223310 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223310\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number of persons be x \r<BR>\n" );
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document.write( "cost will be 30x +600\r<BR>\n" );
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document.write( "50x will be the amount collected.<BR>\n" );
document.write( "if the costs have to be met the revenue must be equal to the collection\r<BR>\n" );
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document.write( "30x+600=50x<BR>\n" );
document.write( "20x =600<BR>\n" );
document.write( "x= 30\r<BR>\n" );
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document.write( "To break even they have to have a minimum of 30 persons.<BR>\n" );
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