document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=312396>Question 312396</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation in slope-intercept form of the line that has a slope of -3 and contains the point (1, 1). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223304 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> They give you one point and slope.  This is all you need to plug into the point-slope formula.\r<BR>\n" );
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document.write( "The point-slope formula is: y - a = m(x - b).\r<BR>\n" );
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document.write( "If (a,b) represents your point, then a = 1 and b = 1.\r<BR>\n" );
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document.write( "If m represents your slope, then m = -3.\r<BR>\n" );
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document.write( "We now plug and chug.\r<BR>\n" );
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document.write( "y - 1 = -3(x - 1)\r<BR>\n" );
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document.write( "y - 1 = -3x + 3\r<BR>\n" );
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document.write( "y = -3x + 3 + 1\r<BR>\n" );
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document.write( "y = -3x + 4\r<BR>\n" );
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document.write( "Done! </SPAN>\n" );
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