document.write( "Question 312381: if e, f, g, and h are consecutive odd integers and e < f < g < h ,then g + h is how much greater than e + f ?\r
\n" ); document.write( "\n" ); document.write( "a 2 b 3 c 4 d 5 e 8
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #223295 by Edwin McCravy(20062)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "If e, f, g, and h were 3, 5, 7, and 9, then g+h would be 7+9=16, and e+f would be 3+5=8, and 16 is 8 greater than 8.\r\n" );
document.write( "\r\n" );
document.write( "If e, f, g, and h were 39, 41, 43, and 45, then g+h would be 43+45=88 and e+f would be 39+41=80, and 88 is 8 greater than 80.\r\n" );
document.write( "\r\n" );
document.write( "If e, f, g, and h were 77, 79, 81, and 83, then g+h would be 81+83=164 and e+f would be 77+79=156, and 164 is 8 greater than 156.\r\n" );
document.write( "\r\n" );
document.write( "Any way you do it, the answer is 8, choice e.  You just have to know what\r\n" );
document.write( "the words \"consecutive\" and \"odd\" mean.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );