document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36427>Question 36427</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The tension T on a cable varies directly as the cube of its surface S, and inversely as the square of its length L. If T=1 when S=2 and L=3, find T for S=4 and L=5/6.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22328 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22328\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The tension T on a cable varies directly as the cube of its surface S, and inversely as the square of its length L. If T=1 when S=2 and L=3, find T for S=4 and L=5/6..\r<BR>\n" );
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document.write( "tension = k(S^3)/L^2<BR>\n" );
document.write( "Need to find \"k\"<BR>\n" );
document.write( "1=k(8)/9<BR>\n" );
document.write( "k=72<BR>\n" );
document.write( "Equation is now T=72(S^3)/L^2<BR>\n" );
document.write( "Find T is S=4 and L=(5/6)<BR>\n" );
document.write( "T=72(4^3)/(5/6)^2<BR>\n" );
document.write( "T=72(64)/[(25/36)]<BR>\n" );
document.write( "T=3200<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "T=<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );