document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=312273>Question 312273</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a train leves at 9 am going 60 mph and another train leaves at 12 noon going 75 mph. how long until the second train catches the first<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223267 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223267\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> train A leaves 9.00am at 60 mph.<BR>\n" );
document.write( "Train B leaves at 12 noon at 75 mph<BR>\n" );
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document.write( "Before train B leaves train A has traveled 60*3 = 180 miles.<BR>\n" );
document.write( "From this point let train A travel x miles before they meet.<BR>\n" );
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document.write( "So train B travels x+180 miles to catch up.<BR>\n" );
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document.write( "time taken by train A = x/60<BR>\n" );
document.write( "time taken by train B = x+180 / 75<BR>\n" );
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document.write( "x/60 = x+180 / 75<BR>\n" );
document.write( "75x = 60(x+180)<BR>\n" );
document.write( "75x=60x +10800<BR>\n" );
document.write( "15x=10800<BR>\n" );
document.write( "x= 720 miles.<BR>\n" );
document.write( "Train B has to travel 720 miles to catch up.<BR>\n" );
document.write( "its speed is 75 mph<BR>\n" );
document.write( "time taken = 720/75<BR>\n" );
document.write( "=9.6 hours </SPAN>\n" );
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