document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=312226>Question 312226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find area of equilateral triangle of side 4a using heron&#146;s formula. using this formula find area of an equilateral triangle whose perimeter is 540cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223251 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> heron's formula <BR>\n" );
document.write( "area of triangle = sqrt(s(s-a)(s-b)(s-c))\r<BR>\n" );
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document.write( "s= half perimeter = 4a+4a+4a /2 = 6a<BR>\n" );
document.write( "Area = sqrt(6a(2a)(2a)(2a))<BR>\n" );
document.write( "area = sqrt48a^4.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "perimeter = 540<BR>\n" );
document.write( "side = 180<BR>\n" );
document.write( "s=270<BR>\n" );
document.write( "area =sqrt(270(90)(90)(90))<BR>\n" );
document.write( "=14029.26 sq cm </SPAN>\n" );
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