document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=312158>Question 312158</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive integers such that the sum of the first and twice the second is 122 minus three times the third. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223219 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x, x+1 & x+2 be the 3 integers.<BR>\n" );
document.write( "x+2(x+1)=122-3(x+2)<BR>\n" );
document.write( "x+2x+2=122-3x-6<BR>\n" );
document.write( "x+2x+3x=122-6-2<BR>\n" );
document.write( "6x=114<BR>\n" );
document.write( "x=19 ans. for the smaller integer.<BR>\n" );
document.write( "19+1=20 ans. for the middle integer.<BR>\n" );
document.write( "19+2=21 ans. for the largest integer integer.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "19+2*20=122-3*21<BR>\n" );
document.write( "19+40=122-63<BR>\n" );
document.write( "59=59  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );