document.write( "Question 312160: The length of a new rectangular playing field is 4 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 578 yards,what are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #223216 by checkley77(12844)\"\" \"About 
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L=4W+4
\n" ); document.write( "P=2L+2W
\n" ); document.write( "578=2(4W+4)+2W
\n" ); document.write( "578=8W+8+2W
\n" ); document.write( "10W=578-8
\n" ); document.write( "10W=570
\n" ); document.write( "W=570/10
\n" ); document.write( "W=57 ANS.
\n" ); document.write( "L=4*57+4
\n" ); document.write( "L=228+4
\n" ); document.write( "L=232 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "578=2*232+2*57
\n" ); document.write( "578=464+114
\n" ); document.write( "578=578
\n" ); document.write( "
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