document.write( "Question 312160: The length of a new rectangular playing field is 4 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 578 yards,what are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #223216 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=4W+4 \n" ); document.write( "P=2L+2W \n" ); document.write( "578=2(4W+4)+2W \n" ); document.write( "578=8W+8+2W \n" ); document.write( "10W=578-8 \n" ); document.write( "10W=570 \n" ); document.write( "W=570/10 \n" ); document.write( "W=57 ANS. \n" ); document.write( "L=4*57+4 \n" ); document.write( "L=228+4 \n" ); document.write( "L=232 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "578=2*232+2*57 \n" ); document.write( "578=464+114 \n" ); document.write( "578=578 \n" ); document.write( " |