document.write( "Question 312145: A car radiator has a 6-liter capacity. If the liquid in the radiators 40% antifreeze, how much liquid must be replaced with pure antifreeze to bring the mixture up to a 50% solutions? \n" ); document.write( "
Algebra.Com's Answer #223169 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Let A be the amount of 40% solution currently in the radiator. You add B liters of pure antifreeze (100% solution). \n" ); document.write( "1. \n" ); document.write( "2. \n" ); document.write( "From eq. 2, \n" ); document.write( " \n" ); document.write( "Substitute into eq. 1, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Then from eq. 2, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "There are currently 5 liters of 40% solution. Adding 1 liter will fill the radiator and make a 50% solution. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |