document.write( "Question 312128: 5. A mutual fund manager is reviewing her account status and finds that the account population is normally distributed with a mean of $60,000 and a standard deviation of $6,000. \r
\n" ); document.write( "\n" ); document.write( "a. If she selects an account at random, what is the probability the account will have a value between $60,000 and $69,000? _______\r
\n" ); document.write( "\n" ); document.write( "b. If she selects an account at random, what is the probability the account will have a value between $51,000 and $66,000? ________\r
\n" ); document.write( "\n" ); document.write( "c. If she selects an account at random, what is the probability the account will have a value less than $55,000? ________\r
\n" ); document.write( "\n" ); document.write( "d. If she selects an account at random, what is the probability the account will have a value greater than $72,000? ________
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Algebra.Com's Answer #223162 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
a) Find the z score for 60000 and 69000
\n" ); document.write( "\"z%2860000%29=%2860000-60000%29%2F6000=0\"
\n" ); document.write( "\"z%2869000%29=%2869000-60000%29%2F6000=1.5\"
\n" ); document.write( "\"P%280%29=0.50000\"
\n" ); document.write( "\"P%281.5%29=0.93319\"
\n" ); document.write( "P(60K< x <69K)=P(1.5)-P(0)=0.93319-0.5=\"highlight_green%280.43319%29\"
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\n" ); document.write( "b) Find the z score for 55000
\n" ); document.write( "\"z%2851000%29=%2851000-60000%29%2F6000=-1.5\"
\n" ); document.write( "\"z%2866000%29=%2866000-60000%29%2F6000=1\"
\n" ); document.write( "\"P%28-1.5%29=0.066807\"
\n" ); document.write( "\"P%281%29=0.841345\"
\n" ); document.write( "P(51K< x < 66K)=0.841345-0.066807=\"highlight_green%280.774538%29\"
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\n" ); document.write( "c) Find the z score for 55000
\n" ); document.write( "\"z%2855000%29=%2855000-60000%29%2F6000=-0.833\"
\n" ); document.write( "\"P%28-0.8333%29=0.202328\"
\n" ); document.write( "P(x <55K)=\"highlight_green%280.202328%29\"
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\n" ); document.write( "d) Find the z score for 72000
\n" ); document.write( "\"z%2872000%29=%2872000-60000%29%2F6000=2\"
\n" ); document.write( "\"P%282%29=0.97725\"
\n" ); document.write( "P(x <72K)=\"0.97725\"
\n" ); document.write( "P(x >72K)=1-P(x <72K)=1-0.97725=\"highlight_green%280.02275%29\"
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