document.write( "Question 311991: y\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #223092 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
First plot, $\"y=x%5E2-12x%2B36\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+x%5E2-12x%2B36%29+\"$
\n" ); document.write( "Now choose a point not on the parabola.
\n" ); document.write( "(0,0) is an available point.
\n" ); document.write( "Test the inequality.
\n" ); document.write( "If the point satisfies the inequality, it's in the solution region.
\n" ); document.write( "If it doesn't, it's not in the solution region\".
\n" ); document.write( "(0,0)
\n" ); document.write( " $\"0%3C0-12%280%29%2B36\"$
\n" ); document.write( " $\"36%3E0\"$
\n" ); document.write( "True, so (0,0) is in the solution region.
\n" ); document.write( "Shade the region containing (0,0).
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Solved by pluggable solver: Plot Any Inequality

Graphing function $\"y%3Cx%5E2-12x%2B36\"$ :
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\n" ); document.write( " $\"graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+y%3Cx%5E2-12x%2B36+%29\"$

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