document.write( "Question 311966: An airplane travels 6030km against the wind in 30 hours and 6750 with the wind in the same amount of time. What is the rate of the plane in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #223069 by mananth(16946)\"\" \"About 
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let the speed of plane in still air be xmph
\n" ); document.write( "speed of wind = y
\n" ); document.write( "..
\n" ); document.write( "against wind speed will be x-y.
\n" ); document.write( "Time traveled = 30 hour
\n" ); document.write( "distance = 6030 miles
\n" ); document.write( "so 30(x-y) = 6030
\n" ); document.write( "..
\n" ); document.write( "with wind speed will be x+y
\n" ); document.write( "time taken = 30 hours
\n" ); document.write( "distance = 6750 miles
\n" ); document.write( "30(x+y)=6750\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "30x-30y=6030
\n" ); document.write( "30x+30y=6750
\n" ); document.write( "ADD
\n" ); document.write( "..
\n" ); document.write( "60x = 12780
\n" ); document.write( "x= 12780/60
\n" ); document.write( "x= 213 mph the speed of plane in still air
\n" ); document.write( "plug the value of x in any equation
\n" ); document.write( "x+y= 225
\n" ); document.write( "213+y=225
\n" ); document.write( "y=12 mph the speed of wind
\n" ); document.write( "
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