document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=311993>Question 311993</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. If one is doubled, the result is 69 degrees less than the other angle. Please find the value of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223067 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223067\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one angle be x deg<BR>\n" );
document.write( "other will be 180-x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "when one is doubled<BR>\n" );
document.write( "2x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "2x+69=180-x<BR>\n" );
document.write( "3x= 111<BR>\n" );
document.write( "x=37 deg.<BR>\n" );
document.write( "the other will be 180 -37<BR>\n" );
document.write( "= 143 deg </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );