document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=311835>Question 311835</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 5 less than twice its length. If the area of the rectangle is 140 cm, what is the length of the diagonal?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #223028 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=223028\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=2L-5<BR>\n" );
document.write( "A=LW<BR>\n" );
document.write( "140=L(2L-5)<BR>\n" );
document.write( "140=2L^2-5L<BR>\n" );
document.write( "2L^2-5L-140=0<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "X=(5+-SQRT(-5^2-4*2*-140])/2*2<BR>\n" );
document.write( "X=(5+-SQRT(25+1,120])/4<BR>\n" );
document.write( "X=(5+-SQRT1,145)/4<BR>\n" );
document.write( "X=(5+-33.8378)/4<BR>\n" );
document.write( "X=(5+33.8378)/4<BR>\n" );
document.write( "X=38.8378/4<BR>\n" );
document.write( "X=9.7 ANS.<BR>\n" );
document.write( "X=(5-33.8378)/4<BR>\n" );
document.write( "X=-28.8378/4<BR>\n" );
document.write( "X=-7.21 ANS. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );